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On this page
  • What is SQL injection (SQLi)?
  • How to detect SQL injection vulnerabilities
  • Retrieving hidden data
  • Subverting application logic
  • Labs 🔬
  1. PortSwigger - Web Security Academy
  2. Server-side vulnerabilities

SQL injection

https://portswigger.net/web-security/learning-paths/server-side-vulnerabilities-apprentice/sql-injection-apprentice/sql-injection/what-is-sql-injection-sqli

What is SQL injection (SQLi)?

SQL injection (SQLi) is a web security vulnerability that allows an attacker to interfere with the queries that an application makes to its database. This can allow an attacker to view data that they are not normally able to retrieve. This might include data that belongs to other users, or any other data that the application can access. In many cases, an attacker can modify or delete this data, causing persistent changes to the application's content or behavior.

In some situations, an attacker can escalate a SQL injection attack to compromise the underlying server or other back-end infrastructure. It can also enable them to perform denial-of-service attacks.

How to detect SQL injection vulnerabilities

You can detect SQL injection manually using a systematic set of tests against every entry point in the application. To do this, you would typically submit:

  • The single quote character ' and look for errors or other anomalies.

  • Some SQL-specific syntax that evaluates to the base (original) value of the entry point, and to a different value, and look for systematic differences in the application responses.

  • Boolean conditions such as OR 1=1 and OR 1=2, and look for differences in the application's responses.

  • Payloads designed to trigger time delays when executed within a SQL query, and look for differences in the time taken to respond.

  • OAST payloads designed to trigger an out-of-band network interaction when executed within a SQL query, and monitor any resulting interactions.

Alternatively, you can find the majority of SQL injection vulnerabilities quickly and reliably using Burp Scanner (pro version).

Retrieving hidden data

Imagine a shopping application that displays products in different categories. When the user clicks on the Gifts category, their browser requests the URL:

https://insecure-website.com/products?category=Gifts

This causes the application to make a SQL query to retrieve details of the relevant products from the database:

SELECT * FROM products WHERE category = 'Gifts' AND released = 1

This SQL query asks the database to return:

  • all details (*)

  • from the products table

  • where the category is Gifts

  • and released is 1.

The restriction released = 1 is being used to hide products that are not released. We could assume for unreleased products, released = 0.

The application doesn't implement any defenses against SQL injection attacks. This means an attacker can construct the following attack, for example:

https://insecure-website.com/products?category=Gifts'--

This results in the SQL query:

SELECT * FROM products WHERE category = 'Gifts'--' AND released = 1

Crucially, note that -- is a comment indicator in SQL. This means that the rest of the query is interpreted as a comment, effectively removing it. In this example, this means the query no longer includes AND released = 1. As a result, all products are displayed, including those that are not yet released.

You can use a similar attack to cause the application to display all the products in any category, including categories that they don't know about:

https://insecure-website.com/products?category=Gifts'+OR+1=1--

This results in the SQL query:

SELECT * FROM products WHERE category = 'Gifts' OR 1=1--' AND released = 1

Subverting application logic

Imagine an application that lets users log in with a username and password. If a user submits the username wiener and the password bluecheese, the application checks the credentials by performing the following SQL query:

SELECT * FROM users WHERE username = 'wiener' AND password = 'bluecheese'

If the query returns the details of a user, then the login is successful. Otherwise, it is rejected.

In this case, an attacker can log in as any user without the need for a password. They can do this using the SQL comment sequence -- to remove the password check from the WHERE clause of the query. For example, submitting the username administrator'-- and a blank password results in the following query:

SELECT * FROM users WHERE username = 'administrator'--' AND password = ''

This query returns the user whose username is administrator and successfully logs the attacker in as that user.

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SQL injection vulnerability in WHERE clause allowing retrieval of hidden data
SQL injection vulnerability allowing login bypass